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Sed (CoderLovesEggs) Paper 1 with Solutions · Q6

Paper 1Algebra

a,ba,b are constants with a>b>0a>b>0. When (a+bx)3(a+bx)^3 is expanded,

  • the sum of the coefficients of xix^i (0≤i≤30\le i\le3) is 2727;
  • the product of the coefficients of xix^i is 99.

It follows that 2a+b2a+b is:

A9+52\dfrac{9+\sqrt5}2;
B9−52\dfrac{9-\sqrt5}2;
C9+132\dfrac{9+\sqrt{13}}2;
D9−132\dfrac{9-\sqrt{13}}2;
E27+772\dfrac{27+\sqrt{77}}2;
F27−772\dfrac{27-\sqrt{77}}2.

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