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Sed (CoderLovesEggs) Paper 1 with Solutions · Q5

Paper 1Sequences & series

Consider the sequence:

  • a1=2a_1=2
  • an=an−1+1an−1−1a_n=\dfrac{a_{n-1}+1}{a_{n-1}-1} for n>1n>1.

The least value of nn for which (∑i=1nai)>5000\left(\displaystyle\sum_{i=1}^n a_i\right)>5000 is:

A66;
B10001000;
C10011001;
D20002000;
E20012001;
FNo such nn exists.

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