Let a1=1a_1=1a1=1 and an+1=an+1ana_{n+1}=a_n+\dfrac1{a_n}an+1=an+an1. Which statement is true? Aan<2na_n<\sqrt{2n}an<2n for all nnnBan>2na_n>\sqrt{2n}an>2n for all nnnCan=2na_n=\sqrt{2n}an=2n for infinitely many nnnDan<3na_n<\sqrt{3n}an<3n for all nnnEan>2n+1a_n>\sqrt{2n+1}an>2n+1 for all nnn