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Y and A Tutoring Paper 2 with Answers and Hints · Q3

Paper 2Logic & proofProbabilityNumber & counting

A child is chosen at random from a group. Each child is equally likely to be chosen.

Which of the following conditions is/are necessary for the probability that the child has a pet to equal exactly 4/94/9?

I Exactly 55 children in the group do not have a pet.

II The number of children in the group is divisible by 44.

III The number of children in the group with a pet is divisible by 33.

Anone of them
BI only
CII only
DIII only
EI and II only
FI and III only
GII and III only
HI, II and III

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