How many solutions does 3sin2x+5sinxcosx−2cos2x=03\sin^2 x+5\sin x\cos x-2\cos^2 x=03sin2x+5sinxcosx−2cos2x=0 have for 0≤x<2π0\le x<2\pi0≤x<2π? A222B333C444D555E666F888