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Qiuyun TMUA Simulation Test Paper 2 · Q17

Paper 2Logic & proofCalculusTrigonometry

Consider the following attempt to solve the integral:

R=∫0πecos⁡x×(sin⁡3x)dxR=\int_0^\pi e^{\cos x}\times(\sin^3x)\dd x
  • I. u=cos⁡x, dudx=−sin⁡x, x=0⇒u=1, x=π⇒u=−1u=\cos x,\ \dfrac{\dd u}{\dd x}=-\sin x,\ x=0\Rightarrow u=1,\ x=\pi\Rightarrow u=-1
  • II. R=∫1−1eu×sin⁡3x×1−sin⁡xduR=\displaystyle\int_1^{-1}e^u\times\sin^3x\times\dfrac1{-\sin x}\dd u
  • III. R=∫1−1−eu(1−u2)duR=\displaystyle\int_1^{-1}-e^u(1-u^2)\dd u
  • IV. R=∫−11eudu−∫−11euu2duR=\displaystyle\int_{-1}^1e^u\dd u-\int_{-1}^1e^uu^2\dd u
  • V. =[eu]−11−[(u2−2u+2)eu]−11=\left[e^u\right]_{-1}^1-\left[(u^2-2u+2)e^u\right]_{-1}^1
  • VI. =e−1e−(e−1e−(2e−2e)+(2e−2e))=0=e-\dfrac1e-\left(e-\dfrac1e-\left(2e-\dfrac2e\right)+\left(2e-\dfrac2e\right)\right)=0

Which one of the following is true?

AThe solution is correct.
BThe solution is wrong; the error arises as a result of (I).
CThe solution is wrong; the error arises as a result of (II).
DThe solution is wrong; the error arises as a result of (III).
EThe solution is wrong; the error arises as a result of (IV).
FThe solution is wrong; the error arises as a result of (V).
GThe solution is wrong; the error arises as a result of (VI).

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