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Qiuyun TMUA Simulation Test Paper 1 · Q15

Paper 1Algebra

Given that for f(x)f(x):

f(x+2)[1−f(x)]=1+f(x)f(x+2)[1-f(x)]=1+f(x)

Now, we know that f(0)=2f(0)=2, f(1)=3f(1)=3. What is the value of f(2028)f(2028)?

A00
B22
C33
D−2-2
E−3-3
F−12-\frac12
G−13-\frac13

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