For k>0k>0k>0, the function f(x)=(k+52)x2+3k2x+6kf(x)=\left(k+\frac52\right)x^2+3k^2x+6kf(x)=(k+25)x2+3k2x+6k has its minimum at x=−1x=-1x=−1. Find kkk. A23\frac2332B−1-1−1C53\frac5335D333E111