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OxbridgeMind TMUA Paper 1 · Q1

Paper 1Algebra

Given that axb3xc2x=5\dfrac{a^xb^{3x}}{c^{2x}}=5 where aa, bb and cc are positive real number then x=x=

Aln⁡5ln⁡a+3ln⁡b−2ln⁡c\dfrac{\ln 5}{\ln a+3\ln b-2\ln c}
B1a+3b+2c\dfrac1{a+3b+2c}
C2ca+3b\dfrac{2c}{a+3b}
Da+3b+2ca+3b+2c
E(a×3b)2c(a\times3b)^{2c}

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