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Official Specimen Paper 2 · Q1

Paper 2Geometry

The radius of the circle 2x2+2y2−8x+12y+15=02x^2+2y^2-8x+12y+15=0 is

A52\sqrt{\frac52}
B112\sqrt{\frac{11}2}
C412\sqrt{\frac{41}2}
D37\sqrt{37}
E67\sqrt{67}

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