Given that y=−log10(1−x)y=-\log_{10}(1-x)y=−log10(1−x) for x<1x<1x<1, find xxx in terms of yyy. Ax=−1log10(1−y)x=-\dfrac1{\log_{10}(1-y)}x=−log10(1−y)1Bx=1+log10yx=1+\log_{10}yx=1+log10yCx=1−log10yx=1-\log_{10}yx=1−log10yDx=1−10−yx=1-10^{-y}x=1−10−yEx=10−y−1x=10^{-y}-1x=10−y−1Fx=101−yx=10^{1-y}x=101−y