Given that ∫01(ax+b)dx=1\int_0^1(ax+b)\dd x=1∫01(ax+b)dx=1 and ∫01x(ax+b)dx=1\int_0^1x(ax+b)\dd x=1∫01x(ax+b)dx=1 find the value of a+ba+ba+b. A−1-1−1B000C111D222E333F444G555