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Official 2022 Paper 2 · Q12

Paper 2Calculus

Place the following integrals in order of size, starting with the smallest.

P=∫012xdxP=\int_0^1 2^{\sqrt{x}}\dd x
Q=∫012xdxQ=\int_0^1 2^x\dd x
R=∫01(2)xdxR=\int_0^1 (\sqrt2)^x\dd x
AP<Q<RP<Q<R
BP<R<QP<R<Q
CQ<P<RQ<P<R
DQ<R<PQ<R<P
ER<P<QR<P<Q
FR<Q<PR<Q<P

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