Find the value of ∫14(3x+4x2)dx.\int_1^4\left(3\sqrt{x}+\frac{4}{x^2}\right)\dd x.∫14(3x+x24)dx. A−0.75-0.75−0.75B7.1257.1257.125C111111D171717E181818F21.87521.87521.875G34.534.534.5