The curve y=x3−6x+3y=x^3-6x+3y=x3−6x+3 has turning points at x=αx=\alphax=α and x=βx=\betax=β, where β>α\beta>\alphaβ>α. Find ∫αβx3−6x+3 dx\int_\alpha^\beta x^3-6x+3\,\dd x∫αβx3−6x+3dx A−82-8\sqrt2−82B−10-10−10C−10+62-10+6\sqrt2−10+62D000E12−8212-8\sqrt212−82F626\sqrt262G121212