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Official 2020 Paper 1 · Q7

Paper 1Algebra

Given that

23x=8(y+3)2^{3x}=8^{(y+3)}

and

4(x+1)=16(y+1)8(y+3)4^{(x+1)}=\frac{16^{(y+1)}}{8^{(y+3)}}

what is the value of x+yx+y?

A−23-23
B−22-22
C−15-15
D−14-14
E−11-11
F−10-10

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