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Official 2019 Paper 1 · Q16

Paper 1Calculus

Given that

2∫01f(x) dx+5∫12f(x) dx=142\int_0^1 f(x)\,\dd x+5\int_1^2 f(x)\,\dd x=14

and

∫01f(x+1) dx=6\int_0^1 f(x+1)\,\dd x=6

find the value of

∫02f(x) dx\int_0^2 f(x)\,\dd x
A−8-8
B−4-4
C−2-2
D22
E44
F295\frac{29}5
G325\frac{32}5
H1414

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