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Official 2017 Paper 1 · Q1

Paper 1Algebra

Given that

dydx=3x2−2−3xx3,x≠0\frac{\dd y}{\dd x}=3x^2-\frac{2-3x}{x^3},\quad x\ne0

and y=5y=5 when x=1x=1, find yy in terms of xx.

Ay=13x3+x−2−3x−1+623y=\frac13x^3+x^{-2}-3x^{-1}+6\frac23
By=x3+12x−2−3x−1+612y=x^3+\frac12x^{-2}-3x^{-1}+6\frac12
Cy=x3+x−2−3x−1+6y=x^3+x^{-2}-3x^{-1}+6
Dy=x3+x−2−x−1+4y=x^3+x^{-2}-x^{-1}+4
Ey=x3+2x−2−x−1+3y=x^3+2x^{-2}-x^{-1}+3
Fy=3x3+x−2−x−1+2y=3x^3+x^{-2}-x^{-1}+2

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