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Official 2016 Paper 1 · Q15

Paper 1Calculus

The least possible value of the gradient of the curve y=(2x+a)(x−2a)2y=(2x+a)(x-2a)^2 at the point where x=1x=1, as aa varies, is

A−494-\dfrac{49}{4}
B−8-8
C−254-\dfrac{25}{4}
D74\dfrac{7}{4}
E4716\dfrac{47}{16}

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