An acute angle θ\thetaθ satisfies sinθ=2cos2θ.\sin\theta=2\cos^2\theta.sinθ=2cos2θ. Find tan2θ\tan^2\thetatan2θ. A17−32\frac{\sqrt{17}-3}{2}217−3B17−14\frac{\sqrt{17}-1}{4}417−1C17+14\frac{\sqrt{17}+1}{4}417+1D17−12\frac{\sqrt{17}-1}{2}217−1E17+12\frac{\sqrt{17}+1}{2}217+1