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MioMath 2024 Paper 2 · Q14

Paper 2Logic & proof

Given that f(x)=ax2+bx+cf(x)=ax^2+bx+c, which of the following is a sufficient condition for there to be a real number kk such that f(∣x∣)=kf(|x|)=k has 4 different real number solutions?

Ab2−4ac<0b^2-4ac<0
Bb=0b=0
Cab<0ab<0
Da>0a>0
Eb2>4acb^2>4ac

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