Given that θ2≤2π\theta^2\le2\piθ2≤2π and sin(θ2)=12\sin(\theta^2)=\dfrac{1}{2}sin(θ2)=21 find the product of all possible solutions for θ\thetaθ. Aπ56\dfrac{\pi\sqrt{5}}{6}6π5B5π236\dfrac{5\pi^2}{36}365π2C−π6-\dfrac{\pi}{6}−6πD7π224\dfrac{7\pi^2}{24}247π2E11π41296\dfrac{11\pi^4}{1296}129611π4F3π216\dfrac{3\pi^2}{16}163π2