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Maths Made Easy TMUA Paper 1 · Q2

Paper 1Sequences & series

A geometric progression has first term aa and common ratio rr. The 1st, 2nd, and 4th terms form an arithmetic progression (in that order).

Given r≠1r\ne1 and the geometric series converges, find the sum to infinity of the geometric series in terms of aa.

Aa(5−1)a(\sqrt5-1)
Ba(5+12)a\left(\frac{\sqrt5+1}{2}\right)
Ca(5−12)a\left(\frac{\sqrt5-1}{2}\right)
Da(3+5)2\frac{a(3+\sqrt5)}2
Ea(5+3)4\frac{a(\sqrt5+3)}4

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