Evaluate ∑r=0∞(310r+110r+1+410r+2)\displaystyle\sum_{r=0}^{\infty}\left(\frac3{10^r}+\frac1{10^{r+1}}+\frac4{10^{r+2}}\right)r=0∑∞(10r3+10r+11+10r+24). A3.143.143.14B3.140.9\dfrac{3.14}{0.9}0.93.14C31.431.431.4D3.149\dfrac{3.14}{9}93.14E3.140.09\dfrac{3.14}{0.09}0.093.14F0.93.14\dfrac{0.9}{3.14}3.140.9G3.141.1\dfrac{3.14}{1.1}1.13.14H1.13.14\dfrac{1.1}{3.14}3.141.1