If α\alphaα is a root of x3+x2+x+1=0x^3+x^2+x+1=0x3+x2+x+1=0 then ∑n=01000αn=\sum_{n=0}^{1000}\alpha^n=n=0∑1000αn= A000B111C−1-1−1Dα+1\alpha+1α+1Eα−1\alpha-1α−1