Given that α\alphaα and β\betaβ are roots of 4x2+7x−3=04x^2+7x-3=04x2+7x−3=0 then 2α−1\dfrac2{\alpha-1}α−12 and 2β−1\dfrac2{\beta-1}β−12 are roots of A4x2+15x+8=04x^2+15x+8=04x2+15x+8=0B4x2−15x+8=04x^2-15x+8=04x2−15x+8=0C4x2+15x−8=04x^2+15x-8=04x2+15x−8=0D4x2−15x−8=04x^2-15x-8=04x2−15x−8=0