If f(x)=1−1xf(x)=1-\frac1xf(x)=1−x1 then f(999)(x)=f^{(999)}(x)=f(999)(x)= [Note: f(n)(x)f^{(n)}(x)f(n)(x) means the composite of fff with itself nnn times] A1−1x1-\frac1x1−x1B111C1+1x1+\frac1x1+x1DxxxE−1x−1\frac{-1}{x-1}x−1−1