Find ∑k=0∞⌊1+8 000 0004k2⌋,\sum_{k=0}^{\infty}\left\lfloor\frac{1+\sqrt{\dfrac{8\,000\,000}{4^k}}}{2}\right\rfloor,k=0∑∞21+4k8000000, where ⌊x⌋\lfloor x\rfloor⌊x⌋ denotes the largest integer less than or equal to xxx. A282628262826B282828282828C283028302830D141414141414E283228322832F200022000\sqrt220002G282428242824H283628362836