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Clavis TMUA Set C Paper 2 · Q2

Paper 2Calculus

Given that

y=x2+1xfor x>0y=\frac{x^2+1}{\sqrt{x}}\quad\text{for }x>0

find the value of dydx\frac{dy}{dx} when x=1x=1.

A−1-1
B00
C12\frac12
D11
E32\frac32
F22

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