Find the value of ∫19(x−1)2x dx.\int_1^9\frac{(\sqrt{x}-1)^2}{\sqrt{x}}\,dx.∫19x(x−1)2dx. A43\frac4334B83\frac8338C143\frac{14}{3}314D163\frac{16}{3}316E666F203\frac{20}{3}320