If α\alphaα and β\betaβ are roots of the equation x2+5x−5=0x^2+5x-5=0x2+5x−5=0, then (1α+1)3+(1β+1)3\left(\dfrac{1}{\alpha+1}\right)^3+\left(\dfrac{1}{\beta+1}\right)^3(α+11)3+(β+11)3 equals A−322-322−322B427\frac4{27}274C−427-\frac4{27}−274D3+53+\sqrt53+5E4+54+\sqrt54+5F5+25+\sqrt25+2