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Beyond Horizon Set 2 Paper 1 · Q17

Paper 1Algebra

Consider six players P1,P2,P3,P4,P5P_1,P_2,P_3,P_4,P_5, and P6P_6. A team consists of two players (Thus, there are 1515 distinct teams). Two teams play a match exactly once if there is no common player. For example, team {P1,P2}\{P_1,P_2\} cannot play with {P2,P3}\{P_2,P_3\}, but will play with {P4,P5}\{P_4,P_5\}. Then the total number of possible matches is

A3636
B4040
C4545
D5454
E5555
F6060

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