TMUA Beyond Horizon Set 2 Paper 1 · Question 13

Consider a rectangular cardboard box of height $3$ , breadth $4$ , and length $10$ units. There is a lizard in one corner $A$ of the box and an insect in the corner $B$ , which is farthest from $A$ . The length of the shortest path between the lizard and the insect along the surface of the box is

\sqrt{5^2+10^2}

units

\sqrt{7^2+10^2}

units

4+\sqrt{3^2+10^2}

units

3+\sqrt{10^2+4^2}

units

5+\sqrt{10^2+7^2}

units

6+\sqrt{10^2+5^2}

units

examday

Beyond Horizon Set 2 Paper 1 · Q13