Let p(x)p(x)p(x) be a continuous function which is positive for all xxx and ∫23p(x) dx=c∫02p(x+42) dx.\int_2^3p(x)\,dx=c\int_0^2p\left(\frac{x+4}{2}\right)\,dx.∫23p(x)dx=c∫02p(2x+4)dx. Then Ac=4c=4c=4Bc=−14c=-\frac14c=−41Cc=14c=\frac14c=41Dc=2c=2c=2Ec=−12c=-\frac12c=−21Fc=12c=\frac12c=21