What is the product of the two values of bbb which satisfy 2(logab)2+ln(b10)ln(a2)−11=loga(b2)logb(a)?2(\log_a b)^2+\frac{\ln(b^{10})}{\ln(a^2)}-11=\log_a(b^2)\log_b(\sqrt a)?2(logab)2+ln(a2)ln(b10)−11=loga(b2)logb(a)? Aa−5/2a^{-5/2}a−5/2Ba−1/2a^{-1/2}a−1/2Ca3/2a^{3/2}a3/2Da4a^4a4Ea6a^6a6F111G000